If you’re anything like me, you’ll be thankful that the last time you had to work out a vexing math sum or tackle an algebraic problem was way back in high school.

I’m well aware that some people are wired to enjoy math, just as certain others (myself included) are wired to loath it. I like to think of myself as more of a creative soul than a logically-thinking one. But hey, everyone’s different.

That said, while I certainly had no love for tackling math in stuffy classrooms packed full of disobedient kids, I have taken something of an unlikely pleasure in solving online problems when and where I find them. It’s all done in my own sweet time of course (and absolutely not in any sort of hurry), but the process of working my way through internet riddles and puzzles is something I’m now quite taken with…

… and I know I’m not the only one. No, it appears there are a whole host of folks out there who pride themselves on being able to spot patterns and work out challenging math problems.

It’s to that end that we decided to put the minds of our beloved readers to the test, with a bran-teasing issue that’s left plenty of people across the internet scratching their heads.

So, got your thinking cap on? Ready for this week’s exercise in mathematical gymnastics? I certainly hope so… because here it comes:

If 1+4=5, 2+5=12, and , then what is the value of 5+8?

Perhaps it’s easier if you see it written out as follows:

1+4=5
2+5=12
3+6=21
5+8=?

Solution one

1 + 4 = 5
2 + 5 = 2 + 2(5) = 12
3 + 6 = 3 + 3(6) = 21
5 + 8 = 5 + 5(8) = 45
ALGORITHM: A + A(B) = C
ANSWER = 45

Solution two

1 + 4 = 1 + 4 + (0) = 5
2 + 5 = 2 + 5 + (5) = 12
3 + 6 = 3 + 6 + (12) = 21
5 + 8 = 5 + 8 + (21) = 34
ALGORITHM: A + B + C’ = C, where C’ is the previous answer
ANSWER = 34

Solution Three

1 + 4 = 5 = 5
2 + 5 = (5 + 2) + (5) = 12
3 + 6 = (7 + 2) + (12) = 21
5 + 8 = (9 + 2) + (21) = 32
ALGORITHM: for {X=5, C = X + C’ , X = X+2 };, where C’ is the previous answer. A and B not used in equation,
ANSWER = 32

Solution Four

1 + 4 = 5
2 + 5 = 7 (base 5) =12
3 + 6 = 9 (base 4) = 21
5 + 8 = 13 (base 3) = 111
ALGORITHM: for {X=6, C = (A + B)^(10 -> X), X -1} (First answer in Base6, then Base 5, then 4, etc…)
ANSWER = 111

Solution Five

1 + 4 = 5
2 + 5 = 7 (base 5) =12
3 + 6 = 9 (base 4) = 21
4 + 7 = 11 (base 3) = 102
5 + 8 = 13 (base 2) (aka binary) = 1101
ALGORITHM: for {X=6, C = (A + B)^(10 -> X), X -1} (First answer in Base6, then
Base 5, then 4, etc…including “missing” numbers
ANSWER = 1101